Originally Posted by Joshmil53
That's much clearer -ln2/(ln2-3ln5). I can't believe I messed something up so easy lol. Oh well, should get some credit.
I hurried through mine w/o thinking all the way. I have a minor in Math so I tend to over-think it and solve too fast. I made a minor error in translating, here it is...
2^(x+1) = 5^(3x)
log2^(x+1) = log 5^(3x)
(x+1)log 2 = (3x)log 5
xlog2 + log2 = 3xlog5
xlog2 - 3xlog5 = -log2
x(log2 - 3log5) = -log2
x = -log2 / (log2 - 3log5)
-this is the form your teacher was asking for...
if you were to solve for x, then you would get .167
It has been a very long time since I have done these, but I am pretty confident this is correct.
Everyone has a plan, until they get hit.
/ Mike Tyson