[Joshmil53]

Originally Posted by dexternjack

I hurried through mine w/o thinking all the way. I have a minor in Math so I tend to over-think it and solve too fast. I made a minor error in translating, here it is...

2^(x+1) = 5^(3x)
log2^(x+1) = log 5^(3x)
(x+1)log 2 = (3x)log 5
xlog2 + log2 = 3xlog5
xlog2 - 3xlog5 = -log2
x(log2 - 3log5) = -log2

x = -log2 / (log2 - 3log5) -this is the form your teacher was asking for...

if you were to solve for x, then you would get .167

It has been a very long time since I have done these, but I am pretty confident this is correct.

It is.