How many 12-1 or 13-1 teams have there been?

[VCDefectors]

I'd be curious to know this. Each win puts us closer to not only having the best regular season in Cowboys history, but also among the top seasons by any club in NFL history. Of course, it will fly under the radar because of New England. But 13-1? Who would have imagined this type of season?

 

[BigDPlayer]

You are absolutely right. Soak it up, this is a special season for the Cowboys and Patriots. They deserve the accolades though, if they go undefeated.

Too bad the Boys will spoil their little perfect party in February!

 

[ThreeSportStar80]

I wish Dallas had won that game back in October because they would be getting all the attention right now...

 

[CaptainMorgan]

I wish Dallas had won that game back in October because they would be getting all the attention right now...

Thats not the game everyone will remember in the end.

 

[LittleBoyBlue]

I'd be curious to know this. Each win puts us closer to not only having the best regular season in Cowboys history, but also among the top seasons by any club in NFL history. Of course, it will fly under the radar because of New England. But 13-1? Who would have imagined this type of season?

How about this.... two teams go 18-1 and one is a complete disappointment

 

[Cajuncowboy]

I absolutly think the pats will lose a game before the end of the season. I don't know why, but I do.

 

[smarta5150]

I absolutly think the pats will lose a game before the end of the season. I don't know why, but I do.

Wishful thinking... I am delusional also.

I am thinking they go 16-0 but will not make it through the playoffs.

 

[LittleBoyBlue]

I absolutly think the pats will lose a game before the end of the season. I don't know why, but I do.

I dont believe it.... actually want them to go undefeated for regular season.

Wishful thinking... I am delusional also.

I am thinking they go 16-0 but will not make it through the playoffs.

I think between the two that losing in the playoffs is the more likely scenario of the two.