Math help...probability.

5Stars

Here comes the Sun...
Messages
40,935
Reaction score
21,696
CowboysZone DIEHARD Fan
Can anyone help me with this problem?
There are 25(x) people interviewing for a job.
10(y) people were selected from the 25 people.

(z) Three(3) Supervisiors did the interviews.
x,,,y,,z.

Eight(8) of ten(10) slected went to two(2) of the three(3) supervisors that did the interviews.

What is the probality that 8 out of 10 people that got the job go to two of the supervisors?

I forgot Algerbra. :confused:

Serious...what is the equasion?


(my friend whant's to know)
 
Hoofbite;3084054 said:
Probability that they went to the same supervisors?

I guess he's saying that all who got hired, came from 2 supervisors, and the other one was a tough cookie, who didn't hire anyone
 
Bob Sacamano;3084067 said:
I guess he's saying that all who got hired, came from 2 supervisors, and the other one was a tough cookie, who didn't hire anyone

Who knows.
 
Based on the way you worded it I would say 100%. 10 people got selected and you said 8 of them went to 2 supervisors. If the question is the probability that 8 went to those 2 supervisors then it would be 100%
 
5Stars;3083799 said:
Can anyone help me with this problem?
There are 25(x) people interviewing for a job.
10(y) people were selected from the 25 people.

(z) Three(3) Supervisiors did the interviews.
x,,,y,,z.

Eight(8) of ten(10) slected went to two(2) of the three(3) supervisors that did the interviews.

What is the probality that 8 out of 10 people that got the job go to two of the supervisors?

I forgot Algerbra. :confused:

Serious...what is the equasion?


(my friend whant's to know)

Were the selected applicants assigned to supervisors at random?
 
Were any of the applicants minority? If not, thats a Rooney rule violation!
 

Staff online

Forum statistics

Threads
474,004
Messages
14,505,859
Members
24,207
Latest member
TomGiantsfan
Back
Top