plasticman
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How do you measure "home field advantage"?
The answer, I believe, is in the definition. Home field advantage is the value measured by the increase in the probability of winning when the game being played at "home" versus being played "away".
Mathematically speaking, this can be measured by subtracting the winning percentage of away games from the winning percentage of home games and comparing that difference with the other teams.
Let's say a team wins 75% of their games at home and 60% of their games away. The "gap", if you will, is 15%.
I have calculated these gaps for all 32 teams over the past 10 seasons, 2011 to 2020. Here are the results:
Rank _ Tm _ diff
1 _ BAL _ 24%
2 _ GNB _ 23%
3 _ MIN _ 21%
4 _ CLE _ 21%
5 _ BUF _ 20%
6 _ IND _ 19%
7 _ NYJ _ 19%
8 _ MIA _ 19%
9 _ NWE _ 18%
10 _ PIT _ 17%
11 _ ARI _ 16%
12 _ SEA _ 16%
13 _ JAX _ 15%
14 _ CIN _ 14%
15 _ NOR _ 14%
16 _ DEN _ 13%
17 _ HOU _ 13%
18 _ PHI _ 9%
19 _ LVR _ 9%
20 _ CAR _ 8%
21 _ NYG _ 8%
22 _ TEN _ 8%
23 _ LAR _ 7%
24 _ LAC _ 6%
25 _ SFO _ 6%
26 _ DET _ 6%
27 _ WAS _ 6%
28 _ ATL _ 5%
29 _ DAL _ 5%
30 _ CHI _ 4%
31 _ KAN _ 3%
32 _ TAM _ 3%
The Baltimore Ravens have the best home field advantage over the past ten seasons. They won 73% of their home games and 49% of their away game which provided the largest gap of all NFL teams.
Note the last place team. Over the past ten seasons the Buc's winning percentage at away games and home games have been virtually identical. There is almost no influence on the team's results when you consider whee the game is located.
It's rather ironic that the first NFL team to gain a home field advantage for the Super Bowl was the NFL team less likely to be influenced by this achievement.
This also implies that any team playing in Tampa Bay against the Bucs will have the least likely chance of being effected by it.
The answer, I believe, is in the definition. Home field advantage is the value measured by the increase in the probability of winning when the game being played at "home" versus being played "away".
Mathematically speaking, this can be measured by subtracting the winning percentage of away games from the winning percentage of home games and comparing that difference with the other teams.
Let's say a team wins 75% of their games at home and 60% of their games away. The "gap", if you will, is 15%.
I have calculated these gaps for all 32 teams over the past 10 seasons, 2011 to 2020. Here are the results:
Rank _ Tm _ diff
1 _ BAL _ 24%
2 _ GNB _ 23%
3 _ MIN _ 21%
4 _ CLE _ 21%
5 _ BUF _ 20%
6 _ IND _ 19%
7 _ NYJ _ 19%
8 _ MIA _ 19%
9 _ NWE _ 18%
10 _ PIT _ 17%
11 _ ARI _ 16%
12 _ SEA _ 16%
13 _ JAX _ 15%
14 _ CIN _ 14%
15 _ NOR _ 14%
16 _ DEN _ 13%
17 _ HOU _ 13%
18 _ PHI _ 9%
19 _ LVR _ 9%
20 _ CAR _ 8%
21 _ NYG _ 8%
22 _ TEN _ 8%
23 _ LAR _ 7%
24 _ LAC _ 6%
25 _ SFO _ 6%
26 _ DET _ 6%
27 _ WAS _ 6%
28 _ ATL _ 5%
29 _ DAL _ 5%
30 _ CHI _ 4%
31 _ KAN _ 3%
32 _ TAM _ 3%
The Baltimore Ravens have the best home field advantage over the past ten seasons. They won 73% of their home games and 49% of their away game which provided the largest gap of all NFL teams.
Note the last place team. Over the past ten seasons the Buc's winning percentage at away games and home games have been virtually identical. There is almost no influence on the team's results when you consider whee the game is located.
It's rather ironic that the first NFL team to gain a home field advantage for the Super Bowl was the NFL team less likely to be influenced by this achievement.
This also implies that any team playing in Tampa Bay against the Bucs will have the least likely chance of being effected by it.