Math help...probability.

5Stars

Here comes the Sun...
Messages
38,781
Reaction score
18,284
CowboysZone LOYAL Fan
Can anyone help me with this problem?
There are 25(x) people interviewing for a job.
10(y) people were selected from the 25 people.

(z) Three(3) Supervisiors did the interviews.
x,,,y,,z.

Eight(8) of ten(10) slected went to two(2) of the three(3) supervisors that did the interviews.

What is the probality that 8 out of 10 people that got the job go to two of the supervisors?

I forgot Algerbra. :confused:

Serious...what is the equasion?


(my friend whant's to know)
 
Hoofbite;3084054 said:
Probability that they went to the same supervisors?

I guess he's saying that all who got hired, came from 2 supervisors, and the other one was a tough cookie, who didn't hire anyone
 
Bob Sacamano;3084067 said:
I guess he's saying that all who got hired, came from 2 supervisors, and the other one was a tough cookie, who didn't hire anyone

Who knows.
 
Based on the way you worded it I would say 100%. 10 people got selected and you said 8 of them went to 2 supervisors. If the question is the probability that 8 went to those 2 supervisors then it would be 100%
 
5Stars;3083799 said:
Can anyone help me with this problem?
There are 25(x) people interviewing for a job.
10(y) people were selected from the 25 people.

(z) Three(3) Supervisiors did the interviews.
x,,,y,,z.

Eight(8) of ten(10) slected went to two(2) of the three(3) supervisors that did the interviews.

What is the probality that 8 out of 10 people that got the job go to two of the supervisors?

I forgot Algerbra. :confused:

Serious...what is the equasion?


(my friend whant's to know)

Were the selected applicants assigned to supervisors at random?
 
Were any of the applicants minority? If not, thats a Rooney rule violation!
 

Forum statistics

Threads
465,324
Messages
13,866,009
Members
23,790
Latest member
MisterWaffles
Back
Top