Motorola
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I’d love it too. Ten home games and seven on the road.
How do you both figure 10 home games \ 7 road games?Good catch I did not notice. Went through it in a hurry.
Home opponents-
BAL + CIN + DET + HOU + NO + NYG + PHL + TB + WAS = 9
Road opponents-
ATL + CAR + CLE + NYG + PHL + PIT + SF + WAS = 8.
I guess your arithmetic assumes the the Panthers road game will be a majority Cowboys crowd...whether it's in Charlotte - like last year -or the game will be in Munich, Germany - which I predict will be scheduled.