links18
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OK, I have asked this in a couple of threads but no clear answer. Many here are suggesting that if we end in a three way tie with the NFC North Winner and Seattle, we can't get the #2 seed. Playoff generators seem to bear this out.
Why is this? Is it the case that in a three way tie, the three way tie breaking procedures are used to rank all three teams for each seed in question? Why do they not use the three way procedures (conference record) to determine the #1 seed and then revert to two way procedures (Head to Head) to settle the remaining two seeds, as per below?
From: http://www.nfl.com/standings/tiebreakingprocedures
"To determine home-field priority among division-titlists, apply Wild Card tie-breakers.
TO BREAK A TIE FOR THE WILD-CARD TEAM
If it is necessary to break ties to determine the two Wild-Card clubs from each conference, the following steps will be taken.
If the tied clubs are from different divisions, apply the following steps.
Three or More Clubs
(Note: If two clubs remain tied after third or other clubs are eliminated, tie breaker reverts to step 1 of applicable two-club format.)"
Then there is this:
"Only one club advances to the playoffs in any tie-breaking step. Remaining tied clubs revert to the first step of the applicable division or Wild Card tie-breakers. As an example, if two clubs remain tied in any tie-breaker step after all other clubs have been eliminated, the procedure reverts to Step 1 of the two-club format to determine the winner. When one club wins the tiebreaker, all other clubs revert to Step 1 of the applicable two-club or three-club format."
I guess there is a difference between being "eliminated" in a tie break and "winning" a tie break. In other words, if a team is "eliminated" in one step they do go back to the two team procedures for the remaining two teams, but if one team "wins" they continue to use the three way procedure to break the tie between the remaining two teams?
Why is this? Is it the case that in a three way tie, the three way tie breaking procedures are used to rank all three teams for each seed in question? Why do they not use the three way procedures (conference record) to determine the #1 seed and then revert to two way procedures (Head to Head) to settle the remaining two seeds, as per below?
From: http://www.nfl.com/standings/tiebreakingprocedures
"To determine home-field priority among division-titlists, apply Wild Card tie-breakers.
TO BREAK A TIE FOR THE WILD-CARD TEAM
If it is necessary to break ties to determine the two Wild-Card clubs from each conference, the following steps will be taken.
If the tied clubs are from different divisions, apply the following steps.
Three or More Clubs
(Note: If two clubs remain tied after third or other clubs are eliminated, tie breaker reverts to step 1 of applicable two-club format.)"
Then there is this:
"Only one club advances to the playoffs in any tie-breaking step. Remaining tied clubs revert to the first step of the applicable division or Wild Card tie-breakers. As an example, if two clubs remain tied in any tie-breaker step after all other clubs have been eliminated, the procedure reverts to Step 1 of the two-club format to determine the winner. When one club wins the tiebreaker, all other clubs revert to Step 1 of the applicable two-club or three-club format."
I guess there is a difference between being "eliminated" in a tie break and "winning" a tie break. In other words, if a team is "eliminated" in one step they do go back to the two team procedures for the remaining two teams, but if one team "wins" they continue to use the three way procedure to break the tie between the remaining two teams?